1.

Refracted ray from an equilateral prism will be parallel to surface is incidence angle is ....... (mu=1.5)

Answer»

`28^@`
`38^@`
`48^@`
`82^@`

Solution :If `r_2 = C` (Critical ANGLE), then REFRACTED ray will be parallel to AC.
`therefore n=(1)/(sinC)`
`thereforesinC=1/n=(1)/(1.5)=0.6667`
`thereforeC=41^@48^@`
`therefore r_2=41^@48.`
Now,`A=r_1+r_2`
`thereforer_1=A-r_2`
`=60^@-41^@48.`
`thereforer_1=18^@12.`

Now using Snell.s law for AB, n = `(sini)/(sinr_1)`
`therefore sini=nxxsinr_1`
`=1.5xxsin^@13.`
`=1.5xx0.3123=0.4684`
`therefore i=28^@`


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