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Refractive index of a thin convex lens is 1.5 and radii of curvature is 20 cm. The parallel rays incident on it intersect at distance .d., then d = ...... cm. |
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Answer» Solution :`1/f=1/d=(mu-1)(1/R_1-1/R_2)` `therefore1/d=(1.5-1)((1)/(20)+(1)/(20))` `therefore1/d=(0.5)/(10)` `therefored=20` CM |
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