1.

Refractive index of a thin convex lens is 1.5 and radii of curvature is 20 cm. The parallel rays incident on it intersect at distance .d., then d = ...... cm.

Answer»

`(20)/(3)`
10
20
40

Solution :`1/f=1/d=(mu-1)(1/R_1-1/R_2)`
`therefore1/d=(1.5-1)((1)/(20)+(1)/(20))`
`therefore1/d=(0.5)/(10)`
`therefored=20` CM


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