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Reimer-Tiemann reaction involves an aryl carbanion/enolate anion and also -"CCl"_(3) derived from the action of strong bases on CHCl_(3), though the latter has only a transient existence decomposing to "CCl"_(2), a highly electron deficient electrophile that attacks the aromatic nucleus, the product from phenoxideion is after acidification, very largely the o-aldehyde plus just a small amount of p-isomer. CO_(2) can attack in a similar mannerto : "CCl"_(2) on phenoxide ion. Following-a similar mechanism, major product will be |
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Answer» o-hydroxybenzoate |
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