1.

Relation between degree of dissociation (alpha) and vant Hoff's factor for BaCI_(2) is

Answer»

`I = 1 + alpha`
`I = 1 + 2 alpha`
`i= 1 - alpha`
`I = 1 - 2 alpha`

Solution :`{:(,BaCI_(2),hArr,BA^(2+),+,2Cl^(-)),("Initial moles",1,,0,,0),("Moles at EQ",1-alpha,,alpha,,2alpha):}`
van't-Hoff FACTOR `i=1-alpha +alpha + 2alpha = 1 + 2alpha`


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