1.

Relative lowering of vapour pressure of a dilutesolutionof glucose dissolved in 1 kgof wateris 0.002. The molality of the solution is .

Answer»

0.004
0.222
0.111
0.021

Solution :Relativeloweringin vapoure PRESSURE , `(p^(@) - p)/(p^(@)) = x_(2) = 0.002`
Molalityof solution MEANS the numberof MOLES of glucose PRESENTIN 100 g of water .
`w_(1)= 1000 g, n_(1) = (1000)/(18) = 55.55`
`(n_(2))/(n_(2) + 55.55) = 0.002`
For dilutesolution , 55.55 + `n_(2) = 55.55`
`THEREFORE n_(2) = 0.002 xx 55.55 = 0.1111`


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