InterviewSolution
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InterviewSolution
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Repeat the previous exercise if the angle between each pair of springs is `120^@` initially. |
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Answer» Correct Answer - `Time period =T=(2pi)/omega=2pisqrt((2m)/(3k))` In this case if the particle m is pushed against C a by distance x. total resultant force acting on man m is given by `F=kx+(kx)/2=(3kx)/2` [Because net force by A and B ] ` sqrt((kx/2)^2+(kx/2)^2+2(kx/2)(kx/2)) cos120^@` `=kx/2` ` :. a=F/m=(2kx)/(2m)` `rarr a/x=(3k)/(2m)=w^2` `rarr omega=sqrt(3k)/(2m)` `:. Time period =T=(2pi)/omega=2pisqrt((2m)/(3k))` |
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