Replace the # with the largest digit to make 56#4 divisible by 6

1.	Replace the # with the largest digit to make 56#4 divisible by 6
Answer» if the NUMBER is divisible by 6 then it is also divisible by 2,3 it is divisible by 2 last digit is 4 now it is divisible by 3 5+6+x+4=15+× we WANT LARGEST digit to REPLACE it 15+1=16 (not divisible by 3) 15+2=17(not divisible by 3) 15+3=18(divisible by 3) 15+4=19(not divisible by 3) 15+5=20(not divisible by 3) 15+6=21(divisible by 3) 15+7=22(not divisible by 3) 15+8=23(not divisible by 3) 15+9=24(divisible by 3) the largest digit is 9 then number is 5694 this is my answer PLEASE brainliest me

Answer»

if the NUMBER is divisible by 6 then it is also divisible by 2,3

it is divisible by 2 last digit is 4

now it is divisible by 3

5+6+x+4=15+×

we WANT LARGEST digit to REPLACE it

15+1=16 (not divisible by 3)

15+2=17(not divisible by 3)

15+3=18(divisible by 3)

15+4=19(not divisible by 3)

15+5=20(not divisible by 3)

15+6=21(divisible by 3)

15+7=22(not divisible by 3)

15+8=23(not divisible by 3)

15+9=24(divisible by 3)

the largest digit is 9

then number is 5694

this is my answer

PLEASE brainliest me

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Replace the # with the largest digit to make 56#4 divisible by 6

if the NUMBER is divisible by 6 then it is also divisible by 2,3

it is divisible by 2 last digit is 4

now it is divisible by 3

5+6+x+4=15+×

we WANT LARGEST digit to REPLACE it

15+1=16 (not divisible by 3)

15+2=17(not divisible by 3)

15+3=18(divisible by 3)

15+4=19(not divisible by 3)

15+5=20(not divisible by 3)

15+6=21(divisible by 3)

15+7=22(not divisible by 3)

15+8=23(not divisible by 3)

15+9=24(divisible by 3)

the largest digit is 9

then number is 5694

this is my answer

PLEASE brainliest me

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