1.

Resistance of 0.2M solution of an electrolyte is 50Omega. The specific conductance of the solution of 0.5M solution of the same electrolyte is 280Omega. The molar conductivity of 0.5M solution of the electrolyte is S m^(2)mol^(-1) is

Answer»

`5xx10^(-4)`
`5xx10^(-3)`
`5xx10^(3)`
`5xx10^(2)`

SOLUTION :`x=1.4S//m`
`R=50Omega`
`M=0.2 `
`K=(1)/(R)xx(l)/(A)`
`implies(l)/(A)=1.4xx50m^(-1)`.
Now, NEW solution has M=0.5, `R=280Omega`
`impliesK=(1)/(R)xx(l)/(A)=(1)/(280)xx1.4xx50=(1)/(4)`
`implies lamda_(M)=(K)/(1000xxM)=((1)/(4))/(1000xx0.5)=(1)/(2000)=5xx10^(-4)`


Discussion

No Comment Found

Related InterviewSolutions