1.

Resistance of a coil is `10Omega` and its self inductance is 5H. Find the energy stored when it is connected with a 100V battery.

Answer» Current in circuit, `I=(V)/(R)=(100)/(10)=10A`
Stored energy in the inductor `=(1)/(2)LI^(2)=(1)/(2)xx5xx(10)^(2)=250J`


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