1.

Resistance of a conductivity cell filed with a solution of an cleetrolyto of concentration 0.1M is 100 Omega. The conductivity of this solution is 1.29 S m ^(-1). Resistance of the same cell when filled with 0.2 M of the same solution is 520 Omega. The molar coonductivity of 0.2 M solution os electrolyte will be

Answer»

`1.24xx10^(-4) SM^(2) MOL ^(-1)`
`12.4 xx10^(-4) Sm^(2) mol ^(-1)`
`124xx10 ^(-4) S m ^(2) mol ^(-1)`
`1240 xx10^(-4) S m ^(2) mol ^(-1)`

SOLUTION :`R= 100Omega , k =1/R ((l)/(A)),`
`l/A`(cell constnat `= 1.29xx10m^(1)`
Given, `R =520Omega , C=0.2M,`
`mu` (molar conductivity)= ?
`mu =k xxV ` (k can be calculated as `k=1/R ((l)/(A))`
now cell constnat is known. )
Here,
`mu =(1)/(520) xx129 XX(1000)/(0.2)xx10^(-6)m ^(3)`
`=12.4xx10^(-4) Sm^(2) mol ^(-1)`


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