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Resistance of a conductivity cell filled with a solution of an electrolyte of concentration 0.1M is 100Omega. The conductivity of this solution is 1.29 S m^(-1). Resistance of the same cell when filled with 0.2M of the samesolution is 520Omega. the molar conductivity of 0.02M solution of the electrolyte will be |
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Answer» `1.24xx10^(-4)Sm^(2)"mol"^(-1)` `=1.29S m^(-1)xx100Omega=129m^(-1)` In the 2nd CASE `x=("cell constant")/("Resistance")` `=(129m^(-1))/(520Omega)= 0.248Omega^(-1)m^(-1)` `^^_(m)=(x)/("MOLARITY")=(0.248Omega^(-1)m^(-1))/(0.02xx10^(3)"mol"m^(-1))` `=124xx10^(-4)Sm^(2)"mol"^(-1)` |
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