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Resistance of a material at 10^(@)C and 40^(@)C are 45Omega and 85Omega respectively. Find its temperature co-efficient of resistance |
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Answer» Solution :`T_(0)=10^(@)C , T=40^(@)C, R_(0)=45Omega, R=85Omega` `ALPHA=(1)/(R_(0))(DELTAR)/(DeltaT)` `alpha=(1)/(45)((85-45)/(40-10))=(1)/(45)((40)/(30))` `alpha=0.0296 "PER"^(@)C` |
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