1.

Resistance of ammeter made by combination of 20Omega galvanometer and 2Omega shunt is ______

Answer»

`0.18Omega`
`1.8Omega`
`18Omega`
`22Omega`

SOLUTION :If RESISTANCE of AMMETER is R, then `1/R=1/G+1/S`
`thereforeR=(GS)/(G+S)=(20xx2)/(20+2)=40/22~~1.8Omega`


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