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Resistance of galvanometer is `500Omega`. Effective resistance of ammeter with shunt is `25 Omega`. What is the value of shunt ?A. `25 Omega`B. `50 Omega`C. `23.6 Omega`D. `26.3Omega`

Answer» Correct Answer - D
`I_s((G)/(S+G))I=((48)/(2+48))I=((48)/(50))I`
Thus , `96%` of total current will pass through shunt of resistance of `2Omega`.


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