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Resistance of wire having diameter 2 mm and length 100 cm is 0.7 Omega, so resistivity of wire = ..... |
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Answer» 14.4 `mu Omega` m R= `(rho L)/(PI r^(2))` `rho = (pi r^(2) R)/(l) = (22)/(7) XX ((10^(-3))^(2) xx 0.7)/(1)` = `2.2 xx 10^(-6) Omega m= 2.2 mu Omega` m |
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