1.

Resistance or coil at 100^(@)C is 4.2 Omega. If temperature co-efficient of resistance of material is 0.004 (""^(@)C)^(-1) so what will be its resistance at 0^(@)C ?

Answer»

`5 Omega`
`3 Omega`
`4 Omega`
`3.5 Omega`

SOLUTION :`3 Omega`
`R_(t)= R_(0) [ 1 + alpha t]`
` therefore R_(0) = (R_(t))/(1 + alpha t)= (4.2)/(1 + 0.004 xx 100) = 3 Omega`


Discussion

No Comment Found

Related InterviewSolutions