1.

Resistance P, Q, R, S in the four sides of Whearstone bridge have respective values 10 Omega, 30 Omega, 20 Omega and 60 Omega. A cell connected across one diagonal has emf 5 V and internal resistance 2 Omega. If resistance ofgalvanometer is 60 Omega then current passing the cell is .....

Answer»

0.2 A
0.15 A
0.17 A
2A

Solution :0.17 A
Resistance of Wheatstone BRIDGE in the balanced condition,
`R = ((10+ 30)(20 + 60))/((10 + 30) + (20+ 60)) = (40 xx 80)/(120) = (80)/(3) OMEGA`
`therefore ` CURRENT through the battery.
`I = (5)/(R + 2) = (5)/((80)/(3)+2) `
`therefore I = (5 xx 3)/(86) = 0.17446 A `
`therefore I = 0.17 A `


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