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Resistances of three resistors are in the proportion connected in parallel, their effective resistance is 6 Omega. Then connect on if these resistance are connect in series so equivalent resistance will be ....... |
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Answer» `36 Omega` SUPPOSE RESISTANCE is R. `therefore`We get three resistance R : 2R : 3R. equivalent resistance on connecting these three resistance in parallel, `(1)/(6) = (1)/(R) + (1)/(2R) + (1)/(3R) = (6 + 3 + 2)/(6R) = (11)/(6R)` `therefore(6R)/(6) = 11 ` `therefore R = 11 Omega` Now each resistance `11 Omega, 22 Omega , 33 Omega` `therefore ` Equivalent resistance in series connection `R_(S) = 11 + 22 + 33 therefore R_(S) = 66 Omega` |
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