1.

Resistivity of 0.5 M electrolytic solution is 10Omegacm, then find out the molar conductivity of solution.

Answer»

SOLUTION :`Lamda_(m)=`molar CONDUCTIVITY of solution
`KAPPA`=specific conductivity of solution
p=resistivity of solution=`10Omegacm=0.1Omegacm`
`kappa=(1)/(p)=(1)/(10)=0.1Omega^(-1)cm^(-1)=0.1" S "cm^(-1)`
CONCENTRATION of solution :
`c=0.5" MOL "L^(-1)=0.5" mol "cm^(-3)`
`=1000xx0.5" mol "m^(-3)`
`=500.0" mol "m^(-3)`
`Lamda_(m)=(1000kappa)/(c)=(1000xx0.1" S "cm^(-1))/(0.05" mol "cm^(-3))`
`=200" S "cm^(3)mol^(-1)`


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