Resolve a weight of 10 N in a direction parallel to a slope inclined a – InterviewSolution

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1.	Resolve a weight of 10 N in a direction parallel to a slope inclined at 45° to the horizontal. ✖️ No spam ✖️ Spam = 10 answers report
Answer» Let the force 10N makes an angle θ with the inclined lineparallel COMPONENT = 10×sinθ N ; PERPENDICULAR component = 10×cosθ N

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