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`RH_(2)` ( ion exchange resin) can replace `Ca^(2+)`d in hard water as. `RH_(2)+Ca^(2+)rarrRCa+2H^(+)` `1 "litre"` of hard water passing through `RH_(2)` has `pH2`. Hence hardness in `pp m "of" Ca^(2+)` is:A. 200B. 100C. 50D. 125 |
Answer» Correct Answer - A `pH=2,[H^(o+)]=10^(-2)M` `[Ca^(2+)]=(10^(-2))/(2)=0.5xx10^(-2)xx40gL^(-1)` `=(0.5xx10^(-2)xx40xx10^(6))/(10^(3))(g)/(10^(6))mL=200ppm` |
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