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Ring of mass M and radius 1m placed on smooth horizontal surface at rest. A particle of same mass M moving horizontally with speed 6 m//s strike the ring and stick to it as shown in figure. Find angular speed of system after collision in rad/sec. |
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Answer» `M(6)((R)/(2))=[(MR^(2))/(2)+M((R)/(2))^(2)+M((R)/(2))^(2)]OMEGA` `3MR = [MR^(2)]omega` `omega=(3)/(R)=3"rad"//"sec"` 
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