Saved Bookmarks
| 1. |
Roforning to previous illustration, what is the time or crossing mo river assuming width of the river is 500 m? |
|
Answer» Solution :`v_(m)=sqrt(v_(mv)^(2)+v_(m)^(2)+2V_(mv)V_(OMEGA)costheta)` `v_(m)=sqrt(v^(2)+4v^(2)-2V.2v.(1)/(2))` `v=(v_(m))/(sqrt3)=v_(MW)` `t=(d)/(v_(mw)costheta)=(500)/((5//sqrt3)sqrt(1-1//4))=(200xxsqrt3)/(sqrt3)=100sec` |
|