InterviewSolution
`f(X) = cos x -1 ` in `[0, 2PI]``f(x) = x ( x - 2)^(2)` in [0,2]f(x) = `3+ (x-1)^(2//3)` in [ 0,3]f(x)` = SIN^(2) x ` in [ 0 ` pi `]
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