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Root 11 minus root 7 upon root 11 + root 7

Answer» HEY!!!
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●I THINK its rationalisation
\frac{ \sqrt{11 - \sqrt{7} } }{ \sqrt{11} + \sqrt{7} }
Rationalising the denominator
We GET,\frac{ \sqrt{11 }- \sqrt{7} }{ \sqrt{11} + \sqrt{7} } \times \frac{ \sqrt{11 }- \sqrt{7} }{ \sqrt{11} - \sqrt{7} } \\ \frac{{ {( \sqrt{11} - \sqrt{7} )}^{2} }}{ ({ \sqrt{11} )}^{2} - ( { \sqrt{7}) }^{2} } \\ \frac{ { \sqrt{11} }^{2} + { \sqrt{7} }^{2} - 2 \times \sqrt{11} \times \sqrt{7} }{11 - 7} \\ \frac{11 + 7 - 2 \sqrt{77} }{3} \\ \frac{17 - 2 \sqrt{77} }{3}
is the answer

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Hope it HELPS!!! :)


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