1.

S^(2-) and SO_(3)^(2-) can be distinguihsed by using

Answer»

`(CH_(3)COO)_(2)Pb`
`Na_(2)[Fe(CN)_(5)NO]`
both (a) and (b)
None of these

Solution :`S^(2-)+(CH_(3)COO)_(2)Pb underset("BLACK ppt.")(PBS DARR) +2CH_(3)COO^(-)`
`S^(2-)+Na_(2)[Fe(CN)_(5)NO]tounderset("violet ppt.")([Fe(CN)_(5)NOS]^(4-))+2Na^(+)`
HENCE, they are distinguished by both the REAGENTS as only `S^(2-)` gives precipitate with these reagents.


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