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`S^(2-)` and `SO_(3)^(2-)` can be distinguihsed by usingA. `(CH_(3)COO)_(2)Pb`B. `Na_(2)[Fe(CN)_(5)NO]`C. both (a) and (b)D. None of these |
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Answer» Correct Answer - C `S^(2-)+(CH_(3)COO)_(2)Pb underset("black ppt.")(PbS darr) +2CH_(3)COO^(-)` `S^(2-)+Na_(2)[Fe(CN)_(5)NO]tounderset("violet ppt.")([Fe(CN)_(5)NOS]^(4-))+2Na^(+)` Hence, they are distinguished by both the reagents as only `S^(2-)` gives precipitate with these reagents. |
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