1.

s. Find three consecutive numbers such that if theyare divided by 10, 17, and 26 respectively, thesam of their quotients will be lo.

Answer»

Let X, (X+1), (X+2) are 3 consecutive numbers.

X/10 + (X+1)/17+ (X+2)/26 =10

L.C.M = 4420

(442(X) +260(X+1) +170(X+2))/4420=10

(442x+260x+260+170x+340)= 4420×10

(442x+260x+170x+260+340)=44200

872x + 600= 44200

872x= 44200- 600

872x= 43600

X= 43600/872

X= 50_____________________________Ist no. (X)= 502nd no.(x+1)= 50+1= 513rd no.(x+2)= 50+2= 52____________________________The 3 consecutive numbers are 50, 51, 52_____________________________



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