1.

S.I. unit of permittivity (e0) ......

Answer»

`C^(2)N^(-1)M^(-2)`
`N^(1)M^(2)C^(-1)`
`N^(1)M^(2)C^(-2)`
`A^(1)M^(-1)C^(0)`

Solution :`F =(q_(1)q_(2))/(4piE_(0)r^(2))`
`therefore E_(0) = (q_(1)q_(2))/(4piFr^(2))`
`therefore` Unit of `E_(0) = ("Coulomb")^(2)/(NM^(2)) = C^(2)N^(-1)m^(-2)`


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