Sakshi sells coffee at a profit of 12% . If he reduces the price by �

1.	Sakshi sells coffee at a profit of 12% . If he reduces the price by ₹ 29 per kg, he would make a loss of 17%. Find the initial selling price per kg of coffee.
Answer» $\sf\large\underline{Let:}$ $\rm{\implies The\: initial\:CP\:_{(coffee)}=x}$ $\sf\large\underline{To\: Find:}$ $\rm{\implies The\: initial\:CP\:_{(coffee)}=?}$ $\sf\large\underline{Solution:}$ To calculate initial price of per kg coffee we have calculate selling price of coffee when profit on 12% and loss on 17% separately here] $\sf\small\underline{Calculate\:SP\: profit\:on\:12\%:}$ $\tt{\implies SP=\dfrac{100+G\%}{100}\times\:CP}$ $\tt{\implies SP=\dfrac{100+12}{100}\times\:x}$ $\tt{\implies SP=\dfrac{112x}{100}}$ $\sf\small\underline{Calculate\:SP\:loss\:on\:17\%:}$ $\tt{\implies SP=\dfrac{100-L\%}{100}\times\:CP}$ $\tt{\implies SP=\dfrac{100-17}{100}\times\:x}$ $\tt{\implies SP=\dfrac{83x}{100}}$ Note here as GIVEN in QUESTION that he would make a loss of 17% when he REDUCES the price by Rs. 29 per kg. It means here Rs. 29 is the DIFFERENCE between initial selling and reducing selling price.] $\tt{\implies SP\:_{(profit\:on\:12\%)}-SP\:_{(loss\:on\:17\%)}=29}$ $\tt{\implies \dfrac{112x}{100}-\dfrac{83x}{100}=29}$ $\tt{\implies \dfrac{112x-83x}{100}=29}$ $\tt{\implies \dfrac{29x}{100}=29}$ $\tt{\implies 29x=2900\implies x=100}$ $\sf\large{Hence,}$ $\rm{\implies The\: initial\:CP\:_{(coffee)}=Rs.100}$

Sakshi sells coffee at a profit of 12% . If he reduces the price by ₹ 29 per kg, he would make a loss of 17%. Find the initial selling price per kg of coffee.

Answer»

$\sf\large\underline{Let:}$

$\rm{\implies The\: initial\:CP\:_{(coffee)}=x}$

$\sf\large\underline{To\: Find:}$

$\rm{\implies The\: initial\:CP\:_{(coffee)}=?}$

$\sf\large\underline{Solution:}$

To calculate initial price of per kg coffee we have calculate selling price of coffee when profit on 12% and loss on 17% separately here]

$\sf\small\underline{Calculate\:SP\: profit\:on\:12\%:}$

$\tt{\implies SP=\dfrac{100+G\%}{100}\times\:CP}$

$\tt{\implies SP=\dfrac{100+12}{100}\times\:x}$

$\tt{\implies SP=\dfrac{112x}{100}}$

$\sf\small\underline{Calculate\:SP\:loss\:on\:17\%:}$

$\tt{\implies SP=\dfrac{100-L\%}{100}\times\:CP}$

$\tt{\implies SP=\dfrac{100-17}{100}\times\:x}$

$\tt{\implies SP=\dfrac{83x}{100}}$

Note here as GIVEN in QUESTION that he would make a loss of 17% when he REDUCES the price by Rs. 29 per kg. It means here Rs. 29 is the DIFFERENCE between initial selling and reducing selling price.]

$\tt{\implies SP\:_{(profit\:on\:12\%)}-SP\:_{(loss\:on\:17\%)}=29}$