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Salt and water is formed by acid-base neutralisation reaction. If ratio of moles of acid & base taken is not similar to the ratio of their stoichiometric coefficient, then one of the component is limiting reagent.Assume no dissociation of water in following reactions. (Base is 80% pure only, take impurity present as inert & non electrolytic ) Select the correct combination for the resulting basic solution. |
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Answer» (I)(iii)(S) `{:(NaOH+,HCL to ,NaCl,+H_2O),(8/40=0.2 "mole",(8xx500)/1000,-,-):}` =0.4 mole `=0.2 "mole" " " 0.2"mole"` Base in L.R.,`[H^+]=0.2 M " " [Na^+]=0.2 M [CL^(-)]=0.4 M` (ii)KOH pure `=(28xx80)/100=22.4 gm` `{:(KOH+,HNO_3to,KNO_3,+H_2O),(22.4/56=0.4 "mole",(2.5xx500)/1000,-,-):}` =0.1 mole `=0.3 "mole" " " 0.1"mole"` Acid in L.R.,`[OH^(-)]=0.3 M " " [K]=0.4 M [NO_3^(-)]=0.1 M` (iii) `{:(Ca(OH)_2+,H_2SO_4to,CaSO_4,+2H_2O["Pure" Ca(OH)_2=37xx0.8=29.6 gm]),(29.6/74=0.4 ,(0.8xx500)/1000=0.4,-,-):}` `[Ca^(2+)]=[SO_4^(2-)]=0.4M` (iv) `{:(BA(OH)_2+,2HBrto,BaBr_2,+2H_2O["Pure" Ba(OH)_2=342xx0.8=,273.6 gm]),(273.6/171=1.6 ,(6.4xx500)/1000=3.2,-,-),(-,-, ,1.6 "mole"):}` `[Ba^(2+)]=1.6 M " " [Br^(-)]=3.2M` |
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