1.

Same amount of electric current is passed through solutions of AgNO_(3) and HCl. If 1.08g of silver is obtained in the first case, the amount of hydrogen liberated at S.T.P. in the second case is

Answer»

`224cm^(3)`
`1.008g`
`112cm^(3)`
`22400cm^(3)`

Solution :According to Faraday.s second law
`("Mass of Ag")/("Mass of H")=("EQUIVALENT mass of SILVER")/("Equivalent mass of hydrogen")`
or `(1.08)/("Mass of H")=(108)/(1)` or mass, `H=0.01g`
`because2.00` gm of `H_(2)` occupies 22400 ml at STP
`therefore 0.01`gm of `H_(2)` will OCCUPY`=(22400xx0.01)/(2)`
`=112cm^(3)`.


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