Same mass of `CH_(4)` and `H_(2)` is taken in container. The partial pressure caused by `H_(2)` isA. `8 //9`B. `1//9`C. `1//2`D. 1

Same mass of `CH_(4)` and `H_(2)` is taken in container. The partial p

1.	Same mass of `CH_(4)` and `H_(2)` is taken in container. The partial pressure caused by `H_(2)` isA. `8 //9`B. `1//9`C. `1//2`D. 1
Answer» Correct Answer - A `N_(CH_(4))=` number of moles of `CH_(4)=(m)/(16)` `N_(H_(2))= ` number of moles of `H_(2) = (m)/(2)` fraction partial pressure of `H_(2)` is `H_(2)=(n_(H_(2)))/(n_(H_(2))+n_(CH_(4)))=((m)/(2))/((m)/(2)+(m)/(16))=((m)/(2))/((9m)/(16))=(8)/(9)`

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Same mass of `CH_(4)` and `H_(2)` is taken in container. The partial pressure caused by `H_(2)` isA. `8 //9`B. `1//9`C. `1//2`D. 1

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