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Sand particles drop vertically at the rate of `2kgs^-1` on a conveyor belt moving horizontally with a velocity of `0.2ms^-1`. The extra force required to keep the belt moving isA. (a) `0.4N`B. (b) `0.08N`C. (c) `0.04N`D. (d) `0.2N` |
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Answer» Correct Answer - A Force required to keep the belt moving `=F` `F=v(dm)/(dt)=0.2xx2=0.4N` Extra power required: `P=Fv=0.4xx0.2=0.08W` Rate of change of kinetic energy is `1/2v^2((dm)/(dt))=1/2(0.2)^2xx2=0.04Js^-1` |
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