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Sandeep constructed a simple pendulum to find the value of 'g' at that place. He observed that the bob of a simple pendulum moves from the mean position to one of the extreme positions in 0.5 s. Using this he determined the (i) time period of the simple pendulum. (ii) number of oscillations the pendulum has under - gone in four seconds and (iii) the frequency of oscillation of the pendulum. What are his answers ? |
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Answer» Solution :(i) Time period, is the time taken to complete one oscillation. One oscillation is one to and fromotion. Hence, time period `T = 0.5 xx 4 = 2 s.` (II) As per the data given, the pendulum PERFORMS TWO OSCILLATIONS in 4 s. (iii) Frequency of oscillation is `(n) = 1//T = (1)/(2s) = 0.5 Hz.` |
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