1.

[Se(H_2 O)_6]^(3+) ion is

Answer»

colourless and DIAMAGNETIC
coloured and OCTAHEDRAL
colourless and paramagnetic
coloured and paramagnetic

Solution :`Sc=[Ar]3D^(1) , 4s^2`
Oxidation state of Sc in `[Sc(H_2 O)_6]^(3+)` is `Sc^(3+)`
`Sc^(3+) = [Ar] 3d^0 , 4s^(0)`
Thus `Sc^(3+)` does not have unpaired ELECTRON, hence it is diamagnetic and colourless.


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