1.

SecA + cosA =2 find sec2A+ cos2A

Answer»

Given -secA+cosA=2 Now FIND Sec2A+cos2AIn this take COMMON 2 so it become 2(secA+cosA) eq1now put value so secA+cosA =2 in EQ 12(secA+cosA)2(2)4 is value of sec2A+cos2A



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