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Section ((G).Valable masSG-1.s A rocket of mass m- 20 kg has M 180kg fuel. The unifom exhaust velocity of the fuel is v, 1.6 kmis.ate the minimum rate of consumption of fuel so that the rocket may rise from the ground.calculate the maximum vertical speed gained by the rocket when the rate of consumption of(i) Alsofuel μ is (g = 10 m/s) &(in 10-2.30)(a) 2 kg/s(b) 20 kg/s

Answer» <p>Velocity of rocket is given as</p><p>v=u ln(M/M-rt)</p><p>wher M is the total mass of rocket + fuel at t=0 sec = 20 +180 =200 kg</p><p>and r rate of fuel consumption =2kg/sec</p><p>u is the velocity of gas ejection w.r.t rocket = 1.6 km/sec</p><p>ultimate velocity is achieved when all the fuel will burn</p><p>ie. M-rt =20 kg</p><p>so v= 1.6 ln(180/20)</p><p> =3.515 km/sec</p>


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