Section14. Factorise 4a2 + b2 + 25c2 - 4ab – 10bc + 20ca. – InterviewSolution

1.

Section14. Factorise 4a2 + b2 + 25c2 - 4ab – 10bc + 20ca.

Answer»

Answer:

(2a-b+5a) (2a-b+5a)

Step-by-step explanation:

4a2 + b2 + 25c2 - 4ab – 10BC + 20CA.

= (2a)^2-(b)^2+(5c)^2-2.2a.b-2.b.5c+2.2a.5c

=(2a-b+5a)^2

=(2a-b+5a) (2a-b+5a)

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