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See the figure here. We have two hollow thin spherical shells A and B of radii R, and R, respectively. Initially as shown in Fig.(i) shell B has a charge + Q which is uniformly distributed over its outer surface but shell B has no charge. At a particular instant the two spherical shells are connected by a thin copper wire as shown in Fig.(ii). After a couple of minutes two spherical shells A and B are disconnected again as shown in Fig.(iii). Now answer the following questions : What is the ratio of final electric potentials of shell A and shell B ? |
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Answer» Solution :When two spherical shells are CONNECTED, ELECTRIC charge flows from shell A toshell B TILL the two acquires a COMMON potential V. So, we have `V_A/V_B = V/V =1/1` |
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