1.

Select and write the corrcet answer : When shunted , the current sensitivity of a galvanometer reduces by a factor of 100. Theresistance of the shunt is

Answer»

`22/33 OMEGA`
`1/3 Omega`
`2/3 Omega`
`3/2 Omega`.

SOLUTION :`(S'_(I))/(S'_(I)) = (theta//I)/(theta//I_(G)) = (I_(G))/I = S/(S+G)`
` :. 1/100 = S/(S+G) "" :. S/(S+G-S) = 1/(100 - 1) "" :. S = G/99 = 66/99 = 6/9 = 2/3 Omega`


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