1.

Select compound having maximum solubility in water.

Answer»

`P=2P_(0)`
`P=4P_(0)//3`
`N=2P_(0)V_(0)..3RT_(0)`
`n=3P_(0)V_(0)//2RT_(0)`

Solution :
NUMBERS of moles =`(P_(0)V_(0))/(RT_(0)) =x`
`(n_(i)R_(0)T_(0))/(V_(0))=(n_(2)R_(0)2T_(0))/(V_(0))`
`n_(2)=1/3xx2x =1/3 xx2 xx(P_(0)V_(0))/(RT_(0))`
`n_(2)=2/3 (P_(0)V_(0))/(RT_(0))`
`P=n_(2)(R(2T_(0)))/(V_(0)) =(2R_(0)V_(0))/(3RT_(0)) xx(R(2T_(0)))/(V_(0))=(4P_(0))/3`


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