InterviewSolution
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InterviewSolution
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Select the correct formula of potential energy in wave energy?(a) \(\frac{PE}{A} = \frac{1}{4}ρa^2 × \frac{g}{g_c}\)(b) PE = \(\frac{1}{4}ρa^2 × \frac{g}{g_c}\)(c) \(\frac{A}{PE} = \frac{1}{4}ρa^2 × \frac{g}{g_c}\)(d) \(\frac{PE}{A} = \frac{1}{4}\)ρa^2 × gThis question was addressed to me in a job interview.I need to ask this question from Wave Energy topic in chapter Ocean Energy & Geothermal Energy of Energy Engineering |
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Answer» CORRECT CHOICE is (a) \(\frac{PE}{A} = \frac{1}{4}ρa^2 × \frac{g}{g_c}\) EXPLANATION: \(\frac{PE}{A} = \frac{1}{4}ρa^2 × \frac{g}{g_c}\) is the correct formula for the potential energy of a wave. g = gravitational acceleration, m/s^2 gc = CONVERSION factor ρ = water density a = amplitude A = λL in J/m^2. |
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