1.

Select the correct order.

Answer»

Graphite = fullerene lt diamond (no. of CARBON atoms connected PER carbon atom with covalent bond only)
NaF lt KCl lt RbBr (electrical conductance in aqueous solution)
NaF lt MgO lt AlN (LATTICE energy)
`Li^(+)(G)gtMg^(2+)(g)gtBe^(2+)(g)` (hydration enegty)

Solution :B.O. in graphite and fullerene `=(4)/(3)`
while in diamond = 1
(b) Ionic mobility of `Rb^(+)gtK^(+)gtNa^(+)`
Ionic mobility of `Br^(-)gtCl^(-)gtF^(-)`
`L.E.prop(q_(+)*q_(-))/(r^(+)+r^(-))`
between charge and size, charge dominates.


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