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Answer» B is OPTICALLY active but `A` does not A is optically active but `B` does not Both `A` and `B` are optically active because of the presence of CHIRAL CENTRES Both `A` and `B` are optically inactive because of the presence of vertical PLANE of symmetry Solution :In a free rotation about the single bond is possible and each ring has a verticle about the single bond is possible and each ring has a verticle plane of symmetry Hence it does not show optical isomerism The diphenyl is sterically hindered because of bulky ORTHO substituents therefore phenyl ring cannot be coplanar and the energey barrier for rotation of `C'-C^(1)` o bond is very high for interconversion of enantiomers .
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