1.

Select the correct statement(s) regarding BF_(2)NH_(2) molecule:

Answer»

FBF bond angle `lt120^(@)`
HNH bond angle `gt109^(@)28'`
HNH bond angle `lt109^(@)28'`
FBF bond angle `gt120^(@)`

Solution :
`2p_(pi)-2p_(pi)` back bonding
According to Bent.s rule there is more p-character in `B-F` bond than in `B-N` bond, Hence FBF is less than `120^(@)`.
As size of `-NH_(2)` group is larger than F-atom hence repulsion between `-NH_(2)` group and F-atom is higher than between two F-atoms.
As LONE pair of N-atom in `NH_(2)` group participate in back bonding hence `H-N-H` is greater than `109^(@)28.`. as hybridization of N is changing from `sp^(3)` towards close to `sp^(2)`


Discussion

No Comment Found

Related InterviewSolutions