1.

Select the diamagnetic complex ion amongst the following complexes (At.no : Fe = 26 , CO = 27)

Answer»

`K_(3)[FE(CN)_(6)]`
`[Co(NH_(3))_(6)]Cl_(3)`
`K_(3)[FeF_(6)]`
`K_(3)[CoF_(6)]`

Solution :Coordination compound /ion having unpaired ELECTRON is paramagnetic in nature while if it has all the electrons paired , it is diamagnetic .
(a) `K_(3) [Fe (CN)_(6)] i.e. , [Fe(CN)_(6)]^(3-) `ion
`""_(26)Fe = [Ar] 3d^(6) 4s^(2) implies Fe^(3+) = [Ar] 3d^(5) , 4s^(0)`

(b) `[Co(NH_(3))_(6)]Cl_(3)` i.e, `[Co(NH_(3))_(6)]^(3+)` ion
`""_(27)Co = [Ar] 3d^(3) 4s^(2) implies Co^(3+) = [Ar] 3d^(6) 4s^(0)`

(c) `K_(3) [Fe F_(6)] i.e., FeF_(6)^(3-)` ion
`""_(26)Fe = [Ar] 3d^(6) 4s^(2) implies Fe^(3+) = [Ar] 3d^(5) 4s^(0)`

(d) `K_(3) [CoF_(6)]i.e., CoF_(6)^(3-) `ion
`""_(27)Co = [Ar] 3d^(7) 4s^(2) implies Co^(3+) = [Ar] 3d^(6)`

Therefore `, [Co(NH_(3))_(6)] CF_(3)` diamagnetic in nature .


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