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Select the least divisible by 15 16 and 20 leaving a remainder of 7 in each case |
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Answer» Answer: 247 is the least number. Step-by-step explanation: The least number DIVISIBLE by 15, 16 and 20 is their LCM. 15 = 3x5 16 = 2x2x2x2 20 = 2x2x5 LCM = 2x2x2x2x3x5 = 240. Since the least number required LEAVES 7 when DIVIDED by 15, 16, 20 the required number is 240 + 7 i.e. 247. |
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