1.

Select the least divisible by 15 16 and 20 leaving a remainder of 7 in each case

Answer»

Answer:

247 is the least number.

Step-by-step explanation:

The least number DIVISIBLE by 15, 16 and 20 is their LCM.

15 = 3x5

16 = 2x2x2x2

20 = 2x2x5

LCM = 2x2x2x2x3x5 = 240.

Since the least number required LEAVES 7 when DIVIDED by 15, 16, 20 the required number is 240 + 7 i.e. 247.



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