InterviewSolution
Saved Bookmarks
| 1. |
Separation between the plates of a parallel plate capacitor is `d` and the area of each plates is `A`. When a slab of material of dielectric constant `k` and thickness `t(t lt d)` is introduced between the plates. Its capacitance becomesA. `(epsilon_(0)A)/(d+t(1-(1)/(K)))`B. `(epsilon_(0)A)/(d+t(1+(1)/(K)))`C. `(epsilon_(0)A)/(d-t(1-(1)/(K)))`D. `(epsilon_(0)A)/(d-t(1+(1)/(K)))` |
|
Answer» Correct Answer - C |
|