1.

Shekar givesa quarter of his sweets to Ramu and thegives 5 sweets to Raju. He has 7 sweets left how many did he have to start with​

Answer»

Answer:

Step-by-step explanation:

let the number of sweets be Z

sweets are given to RAMU =  1/4 of z

sweets are given to RAJU = 5

the number of sweets LEFT = 7

A/Q

z/4 + 5 + 7 = z

z + 12 = z x 4

z + 12 = 4z

now you can solve



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